In general, to bring an equation of the form:
y2=Ax4+Bx3+Cx2+Dx+q2
into the Weierstraß form, the used substitution is given by using:
Q=2q ,X=(Q(y+q)+Dx)⋅1x2 ,Y=(Q2(y+q)+Q(Cx2+Dx)−D2x2/Q)⋅1x3 . Backwards:x=(Q(X+c)−D2/Q)⋅1Y ,y=−q+x(xX−D)/Q .
Note that it is needed to have a square as the free coefficient in the quartic Ax4+Bx3+Cx2+Dx+q2 on the RHS of the equation we start with.
Reference: [Ian Conell, Elliptic Curves Hanbook, page 105, Quartic to Weierstrass] .
In our case, the free coefficient is −1, so we really need to pass to the Gaussian field Q(i). The following code gives the transformation:
sage: F.<j> = QuadraticField(-1)
sage: R.<X,Y> = PolynomialRing(F)
sage: A, B, C, D, q = 1, 0, 81473/1024, 0, j
sage: Q = 2*q
sage: x = (Q*(X+C) - D^2/Q) / Y
sage: y = -q + x*(x*X - D) / Q
sage: factor( y^2 - (A*x^4 + B*x^3 + C*x^2 + D*x + q^2) )
(-4) * Y^-4 * (X + 81473/1024)^3 * (X^3 + 81473/1024*X^2 - Y^2 + 4*X + 81473/256)
So the given quartic is birationally (there are some other factors...) equivalent to
Y2=X3+81473/1024X2+4X+81473/256 .
So we obtain an elliptic curve with the following minimal model:
sage: E = EllipticCurve( QQ, [ 0, 81473/1024, 0, 4, 81473/256 ] )
sage: EM = E.minimal_model()
sage: EM
Elliptic Curve defined by y^2 + x*y + y = x^3 + x^2 - 138026392*x + 629434426201 over Rational Field
sage: EM.discriminant().factor()
-1 * 2^16 * 46229^2 * 143677^2
Alternative blind code to obtain the above curve is as follows:
sage: R.<x,y> = QQ[]
sage: C = Curve( -y^2 + x^4 + 81473/1024*x^2 - 1 )
sage: JC = Jacobian(C)
sage: JCM = JC.minimal_model()
sage: JC
Elliptic Curve defined by y^2 = x^3 - 6625266817/3145728*x + 543881033738945/14495514624 over Rational Field
sage: JCM
Elliptic Curve defined by y^2 + x*y + y = x^3 + x^2 - 138026392*x + 629434426201 over Rational Field
sage: JCM.discriminant().factor()
-1 * 2^16 * 46229^2 * 143677^2
(But doing this blindly does not provide a way to see which points correspond to which points.)
The point (1,i,0) does not lie on the curve, though (i,1,0) does; but the equation in x,y,z is not homogeneous, and if you homogenize w.r.t. z then the point is no longer on the curve. So are you sure about this data?