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Evaluation of triangle inequality

asked 2019-12-20 19:27:45 +0200

Minhtri gravatar image

updated 2020-10-11 23:16:49 +0200

slelievre gravatar image

I wrote the following code:

x = var('x')
y = var('y')
z = var('z')

expr = abs(x-y)+abs(y-z) >= abs(x-z)

Then I run it:

sage: bool(expr)

The expression is obviously mathematically correct. How come Sage returns "False"?

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answered 2019-12-21 11:37:23 +0200

Emmanuel Charpentier gravatar image

updated 2019-12-21 11:44:07 +0200

Sage implements booleans,and answers to a"logical" query either by True, which means that Sage can compute an equality, or False, meaning that Sage cannot compute this equality. This does not mean that the result is false, only that Sage cannot prove it.

Mathematica does the same:

sage: %%mathematica
....: P = Abs[x - y] + Abs[y - z] >= Abs[x - z]
....: Assuming[x \[Element] Reals && y \[Element] Reals && z \[Element] Reals, Re
....: duce[P]]
        Abs[x - y] + Abs[y - z] >= Abs[x - z]
Out[3]= Abs[y - z] >= -Abs[x - y] + Abs[x - z]

Contrast this with Maxima:

sage: %%maxima
....: declare(x,real,y,real,z,real);
....: is(abs(x-y)+abs(y-z)>=abs(x-z));

Maxima implements "trinary logicals", i. e. a logical value can be true (i. e. the result can be computed true), false(the result can be cimputed false) or unknown (the result cannot be computed).


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Asked: 2019-12-20 19:27:45 +0200

Seen: 459 times

Last updated: Oct 11 '20