(Geometric) Genus of a curve equals to -1 in SageMath

asked 2019-12-08 12:57:00 +0200

azerbajdzan gravatar image

updated 2019-12-08 13:07:09 +0200

What does it mean when Sage computes genus of a projective plane curve to be -1?


x,y,z = QQ['x,y,z'].gens()
C = Curve(x^4 + 10*x^2*y*z + 5*y^2*z^2)


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Not a smooth curve.

sage: C.is_smooth()
FrédéricC gravatar imageFrédéricC ( 2019-12-08 18:47:15 +0200 )edit

C is not geometrically irreducible: over $\mathbb{Q}(\sqrt{5})$ it splits into two components. So, the Euler characteristic of the desingularization ends up being $\chi=-4$. Using the formula $\chi=2g-2$, you end up with genus $-1$. I'm not saying this is a mathematically correct answer; just that this is probably how the answer is discovered: basically by computing the degree of the canonical bundle.

nbruin gravatar imagenbruin ( 2019-12-09 09:09:02 +0200 )edit