linear algebra derivative expressions

Tintin1
41 ●3

How do I differentiate $\mathbf{y}=\mathbf{A}\mathbf{x}$ symbolically in sagemath with respect to the vector $\mathbf{x}$ ? The result is obviously $\mathbf{A}$ . Similarly, I would like to be able to calculate the derivative of the quadratic form $\alpha=\mathbf{x}'\mathbf{A}\mathbf{x}$ . I would need these calculations in a more complex setting.

I started off with sympy as follows

from sympy import *
n=7 
A = MatrixSymbol('A', n, n)
x = MatrixSymbol('x', n, 1)

Or is there a different library from sympy available for such a problem?

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answered 5 years ago

Emmanuel Charpentier
7804 ●8 ●52 ●155

I'm out of my depth here, but I'd suggest a look at the Manifolds project, implemented in Sagemath.

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answered 5 years ago

nbruin
4153 ●3 ●45 ●91

I assume your matrix A has entries that do not depend on the entries of x? Then with $y=Ax$ you already define $y$ to be a linear function in $x$ , so the derivative of $y$ with respect to $x$ is simply $x\mapsto A$ .

Similarly, assuming that $A$ a symmetric matrix that is independent of $x$ (otherwise your function doesn't deserve the name quadratic form) you have that the total derivative of $\alpha$ with respect to $x$ is simply $x\mapsto x^t A$ .

No computation necessary; just a calculus book.

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You are right, but I am trying to create a procedure for much more complicated algebraic expressions.

Tintin1 ( 5 years ago )

I suspect you have to write things out in explicit variables then. It looks like you basically want to work with a fairly general vector field. I'm not so sure a computer algebra system can help you much with that without you doing some pretty specific preprocessing. The examples you gave are (trivially) resolved. Perhaps a different example closer to what you want to accomplish would help.

nbruin ( 5 years ago )

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