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How to find the coefficient of a boolean function with respect to some variable?

asked 2019-10-30 01:15:15 -0600

Rahul gravatar image

Suppose we have a boolen ring with variable x1,x2,x3,v1,v2 and v3. let f = 1+x1x2v1v2 + x3v1v2 + v1v3 +x1x2v3. now how i find coefficient of v1v2? in this case it will be (x1x2 + x3). how can i find this using sagemath. I try to use f.coefficient(v1*v2). But it not work.

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Emmanuel Charpentier gravatar imageEmmanuel Charpentier ( 2019-10-31 03:41:46 -0600 )edit

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answered 2019-10-31 03:40:23 -0600

Emmanuel Charpentier gravatar image

Apparently, you want to treat the x as coefficients and the v as indeterminates. One way do do this is to create a ring of polynomials in x1, x2, x3overGF(2) :

sage: R1.<x1, x2, x3>=GF(2)[]
sage: R1
Multivariate Polynomial Ring in x1,

then a ring of polynomials in v1, v2, v3over the latter :

sage: R.<v1, v2, v3>=R1[]
sage: R
Multivariate Polynomial Ring in v1, v2, v3 over Multivariate Polynomial Ring in x1, x2, x3 over Finite Field of size 2

Define f pver this one: sage: f = 1+x1x2v1v2 + x3v1v2 + v1v3 +x1x2v3

and, lo !, it works as you intended:

sage: f.coefficient(v1*v2)
x1*x2 + x3

There are probably other ways to do this.

HTH,

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Asked: 2019-10-30 01:15:15 -0600

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Last updated: Oct 31