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Compute the square root of a complex matrix

asked 2019-06-26 05:21:03 -0500

tobiasBora gravatar image

updated 2019-06-26 06:37:03 -0500

Hello,

I can't find how to compute the square root of a complex matrix... I tried m.sqrt(), sqrt(m) (display only symbolic sqrt), sqrt(m).n()... None of them work. What is the regular way to compute the root of a complex matrix? (you can assume the matrix is self-adjoint if needed).

Thanks!

def test():
    phi = matrix(CC, [[1/sqrt(2)],[i]])
    m = phi * phi.C.T
    print("Matrix: {}".format(m))
    s = sqrt(m).n() # Does not work: AttributeError: 'ComplexField_class_with_category' object has no attribute 'complex_field'
    #s = m^(1/2) # Does not work either, NotImplementedError: non-integral exponents not supported
    # s = m.sqrt() # Does not work either, no attribute sqrt
    print("Sqrt: {}".format(s))
    print("s*s: {}".format(s*s))
    if s*s == m:
        print("Ok")
    else:
        print("Nope :(")

EDIT: For now I'm using the numpy backend with manual diagonalisation, but I'd like to know if there is a better way to proceed...

 phi = matrix(CDF, [[1/sqrt(2)],[i]])
 D, P = m.eigenmatrix_right()
 s = P*diagonal_matrix([sqrt(x) for x in D.diagonal()])*P^-1
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answered 2019-06-26 08:07:23 -0500

slelievre gravatar image

updated 2019-06-30 06:36:50 -0500

One way would be to use the "symbolic n-th power of a matrix".

Define the matrix m with coefficients in QQbar, the field of algebraic numbers:

sage: phi = matrix(QQbar, [[1/sqrt(2)],[i]])
sage: m = phi * phi.C.T
sage: m
[                   1/2 -0.7071067811865475?*I]
[ 0.7071067811865475?*I                      1]

Define a symbolic variable in Sage's symbolic ring:

sage: n = SR.var('n')

Take the n-th power of m:

sage: mn = m^n
sage: mn
[           1/3*3^n/2^n -1/3*I*sqrt(2)*3^n/2^n]
[ 1/3*I*sqrt(2)*3^n/2^n            2/3*3^n/2^n]

Substitute 1/2 to the exponent n:

sage: msqrt = mn.subs({n: 1/2})
sage: msqrt
[1/6*sqrt(3)*sqrt(2)      -1/3*I*sqrt(3)]
[      1/3*I*sqrt(3) 1/3*sqrt(3)*sqrt(2)]

The result has coefficients in Sage's symbolic ring.

To convert it to another ring, use change_ring:

sage: msqrt.change_ring(QQbar)
[   0.4082482904638630? -0.5773502691896258?*I]
[ 0.5773502691896258?*I    0.8164965809277260?]

Check that squaring the square root gives back the original matrix:

sage: msqrt^2
[           1/2 -1/2*I*sqrt(2)]
[ 1/2*I*sqrt(2)              1]
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Asked: 2019-06-26 05:21:03 -0500

Seen: 48 times

Last updated: Jun 30