roots of third degree polynomial
roots of polynomial x^3+7x+25 over field F(37)
roots of polynomial x^3+7x+25 over field F(37)
It may be well a homework, but maybe one should give the solution, since part of it is knowing the right method to be used in the right context. The following initializes the polynomial ring $\Bbb F_{37}[X]$ in the transcendental variable $X$, an other one as the $x$ set by default, and maybe not the $x$ in the OP. Then having the polynomial over the right field we simply ask for its roots. A second solution would be to use a "polynomial expression" using the variable x
, which exists by default (or create any other), then use the method roots
also specifying as optional parameter the ring for the roots.
sage: var('x');
sage: R.<X> = PolynomialRing(GF(37))
sage: (x^3 + 7*x + 25).roots(ring=GF(37))
[(5, 1)]
sage: (x^3 + 7*x + 25).roots(ring=GF(37), multiplicities=False)
[5]
sage: (X^3 + 7*X + 25).roots()
[(5, 1)]
sage: (X^3 + 7*X + 25).roots(multiplicities=False)
[5]
With a field of size 37, you can also use brute force: f = X^3 + 7*X + 25
and then [y for y in GF(37) if f(y) == 0]
.
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Asked: 2019-06-09 16:56:26 +0100
Seen: 375 times
Last updated: Jun 13 '19
What have you tried?
Homework ?