The function f: ℝ → ℝ defined by f(x) = 7x is onto because for any real number r, we have that r/7 is a real number and f(r/7) = r. Consider the same function defined on the integers g: ℤ → ℤ by g(n) = 7n. [closed]
Explain why g is not onto ℤ and give one integer that g cannot output
Closed for the following reason
question is off-topic or not relevant by
slelievre
close date 2019-04-11 01:33:47.918571
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