The function f: ℝ → ℝ defined by f(x) = 7x is onto because for any real number r, we have that r/7 is a real number and f(r/7) = r. Consider the same function defined on the integers g: ℤ → ℤ by g(n) = 7n. [closed]

asked 2019-04-10 16:12:49 -0500

monme gravatar image

updated 2019-04-10 18:33:28 -0500

slelievre gravatar image

Explain why g is not onto ℤ and give one integer that g cannot output

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Closed for the following reason question is off-topic or not relevant by slelievre
close date 2019-04-10 18:33:47.918571