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Factor a solve output

asked 2019-03-08 00:25:05 +0100

tidesson gravatar image

I am new to sage. So, sorry if my question is too trivial.

I can not factor the output of "solve". For instance, this very simple example

x= var('x')
sols=solve(x==6, x)
factor(sols[0].right())

gives me

6

Why I am not getting the following?

2 * 3

which of course is the output of

factor(6).

PS: I guess that the "type" is a crucial thing here, but anyways I'd need to factor 'sage.symbolic.expression.Expression'

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answered 2019-03-08 08:02:33 +0100

Emmanuel Charpentier gravatar image

factor does not mean the same thing in $\mathbb{Z}$ (or $\mathbb{Q}$) and in SR: if, on both cases, factor aims at (recursively) transforming its input in a product of "simpler" elements, the meaning of "simpler" differs:

  • In $\mathbb{Z}$ (or $\mathbb{Q}$), the "simplest" elements are primes;

  • in SR, they are (roughly) polynomials.

In SR, 6 is already a monomial, hence a non-simplifiable element, whereas, in $\mathbb{Z}$, it is not a prime, hence factorizable as a product of primes.

Another illustration:

sage: factor(6/5)
2 * 3 * 5^-1
sage: factor(SR(6/5))
6/5

HTH,

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Comments

Just for completeness, to get the expected answer in the OP, it suffices to convert to integer the output of solve :

sage: factor(ZZ(sols[0].right()))
2 * 3
Juanjo gravatar imageJuanjo ( 2019-03-08 11:57:04 +0100 )edit

Another, more pythonic way, would be :

ZZ((x==6).solve(x)[0].rhs()).factor()
Emmanuel Charpentier gravatar imageEmmanuel Charpentier ( 2019-03-08 18:02:18 +0100 )edit

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Asked: 2019-03-08 00:25:05 +0100

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Last updated: Mar 08 '19