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How to define Qp(5) and Qp(5,3) and find their valuation rings for p=7?

asked 6 years ago

anonymous user

Anonymous

updated 6 years ago

FrédéricC gravatar image

I tried finite extension (Qp I unable do it. It will also great if help me with how to define the valuation ring of that finite extension

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answered 6 years ago

nbruin gravatar image

updated 6 years ago

Try:

sage: Qp=pAdicField(7)
sage: R.<x>=Qp[]
sage: K.<a>=Qp.extension(x^2-5)
sage: OK=K.integer_ring()
sage: OK
7-adic Unramified Extension Ring in a defined by x^2 - 5

Note that 15 is a square in Q7, so Q7(3,5) is just Q7(5).

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I wanted to define \mathbb{Q}_7(\sqrt{5},sqrt{3})

Sunil pasupulati gravatar imageSunil pasupulati ( 6 years ago )

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Asked: 6 years ago

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Last updated: Apr 03 '19