I will start an answer, but the question is not clear to me at all.
First of all, what i understand.
Let R be the ring
R=F2[x,y,z]
fixed once for all times here to have an easy typing.
Now we consider a submodule of a free module over R. It is not clear for me, if we work with the submodule
L=[R R R][0001+x+y+xy1+y+z+yz1+x+z+xz1+z1+x000001+x1+y000]
of the "free row module" [R R R R R R]=R6, or rather with the submodule
M=[0001+x+y+xy1+y+z+yz1+x+z+xz1+z1+x000001+x1+y000][RRRRRR]
of the "free column module"
[RRR]=R3, but in both cases we can do the same with the corresponding module Rn. (Here, n is either 3 or 6.)
The wiki page Gröbner basis tells us to look at the ring R⊕Rn, with the one from R⊕0 and so that multiplying two elements of 0⊕Rn we get zero. In sage, we can use for this the ring Q
from
sage: R.<x,y,z,E1,E2,E3> = PolynomialRing(GF(2))
sage: R
Multivariate Polynomial Ring in x, y, z, E1, E2, E3 over Finite Field of size 2
sage: Q = R.quotient( [e*ee for e in [E1,E2,E3] for ee in [E1,E2,E3]] )
sage: Q
Quotient of Multivariate Polynomial Ring in x, y, z, E1, E2, E3
over Finite Field of size 2
by the ideal (E1^2, E1*E2, E1*E3, E1*E2, E2^2, E2*E3, E1*E3, E2*E3, E3^2)
Above, i took n=3 and there were also some manual rearrangements of output....
We now "only have to implement the generators" of R⊗Rn correspondingly, and ask for the Gröbner basis.
So here is the one possibility with n=6, if i correctly understood the submodule.
Then one can try:
sage: R.<x,y,z,E1,E2,E3,E4,E5,E6> = PolynomialRing(GF(2))
sage: E_List = [E1, E2, E3, E4, E5, E6]
sage: A = matrix(R, 3, 6,
....: [0,0,0,(1+x)*(1+y),(1+y)*(1+z),(1+z)*(1+x),
....: 1+z,1+x,0,0,0,0,
....: 0,1+x,1+y,0,0,0])
sage: gens = [e*ee for e in E_List for ee in E_List] + list(A*vector(R, E_List))
sage: Q = R.quotient(gens)
sage: J = R*gens
sage: J.groebner_basis()
Polynomial Sequence with 24 Polynomials in 9 Variables
(I have to submit... loosing connection soon...)
The submodule in the denominator is: [0001+x+y+xy1+y+z+yz1+x+z+xz1+z1+x000001+x1+y000]F2[x,y,z]6 ?
Thanks. Yes, I made the correction.