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Extended Euclidean Algorithm for Univariate Polynomials with Coefficients in a Finite Field

asked 2018-11-22 10:46:07 +0100

Jsevillamol gravatar image

updated 2018-11-22 10:48:25 +0100

Consider the following snippet, intended to compute the extended euclidean algorithm for polynomials in $F_q[x]$.

def extended_euclides(a,b,quo=lambda a,b:a//b):
    r0 = a; r1 = b
    s0 = 1; s1 = 0
    t0 = 0; t1 = 1

    while r1 != 0:
        q = quo(r0, r1)
        r0, r1 = r1, r0 - q * r1
        s0, s1 = s1, s0 - q * s1
        t0, t1 = t1, t0 - q * t1

    return r0, s0, t0

GFX.<x> = GF(5)[x]
g = x^3 + 2*x^2 - x - 2
h = x - 2
r,s,t = extended_euclides(f,g)
print("The GCD of {} and {} is {}".format(g,h,r))
print("Its Bézout coefficients are {} and {}".format(s,t))
assert r == gcd(g,h), "The gcd should be {}!".format(gcd(g,h))
assert r == s*g + t*h, "The cofactors are wrong!"

Executing this snippet produces the following output:

The GCD of x^3 + 2*x^2 + 4*x + 3 and x + 3 is 3*x + 1
Its Bézout coefficients are 2*x + 4 and 3*x^2 + 4

Error in lines 45-45
Traceback (most recent call last):
  File "/cocalc/lib/python2.7/site-packages/smc_sagews/sage_server.py", line 1188, in execute
    flags=compile_flags) in namespace, locals
  File "", line 1, in <module>
AssertionError: The gcd should be 1!

That is, my code disagrees with sagemath's gcd function, and I think sagemath's result is correct; g(2)!=0, so g and h should not have common factors.

Why is mine wrong?

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1 Answer

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answered 2018-11-22 14:26:40 +0100

rburing gravatar image

See Wikipedia - Polynomial extended Euclidean algorithm:

A third difference is that, in the polynomial case, the greatest common divisor is defined only up to the multiplication by a non zero constant. There are several ways to define the greatest common divisor unambiguously. In mathematics, it is common to require that the greatest common divisor be a monic polynomial. To get this, it suffices to divide every element of the output by the leading coefficient of $r_k$. This allows that, if a and b are coprime, one gets 1 in the right-hand side of Bézout's inequality. Otherwise, one may get any non-zero constant.

So e.g. at the end you can do

lc = r0.lc()
return r0/lc, s0/lc, t0/lc
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Comments

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Any ideas on how to implement this without breaking the code for other types of euclidean domains which are not polynomial rings (eg integers and gaussians)?

Jsevillamol gravatar imageJsevillamol ( 2018-11-25 18:40:42 +0100 )edit
1

EDIT: I found out I can use sage.rings.polynomial.polynomial_ring.is_PolynomialRing to selectively apply this solution

Jsevillamol gravatar imageJsevillamol ( 2018-11-25 18:58:22 +0100 )edit

Ah yes, I missed that. Nice find.

rburing gravatar imagerburing ( 2018-11-25 22:33:47 +0100 )edit

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Asked: 2018-11-22 10:46:07 +0100

Seen: 3,366 times

Last updated: Nov 22 '18