I'm certain that the question is not correctly asked. Notice that in the sentence,
How can I calculate this sum?
1/1-(x+x^2)^2
there is no sum at all!
However, it seems that the OP wants to know if the expresion $$\frac{1}{1 - (x + x^2)^2} = \sum_{n = 0}^\infty (x + x^2)^{2n},$$ is valid.
If that is the question... I'd say yes, as long as $(x + x^2)^2 <1.$
It seems you want the power series expansion of $1 / (1 - (x + x^2)^2))$.
It is not clear if you want the first few terms of this power series, or a formula for the general term.
To get the first few terms, you can use the method .series().
sage: x = SR.var('x')
sage: f = 1/(1-(x+x^2)^2)
sage: f.series(x)
1 + 1*x^2 + 2*x^3 + 2*x^4 + 4*x^5 + 7*x^6 + 10*x^7 + 17*x^8 + 28*x^9 + 44*x^10
+ 72*x^11 + 117*x^12 + 188*x^13 + 305*x^14 + 494*x^15 + 798*x^16 + 1292*x^17
+ 2091*x^18 + 3382*x^19 + Order(x^20)
See also OEIS sequence A094686 for more on this series.
Asked: 2018-08-13 18:24:41 +0100
Seen: 601 times
Last updated: Aug 28 '18
Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.
I'm afraid that your formula is not correct :
This can be shown in an elementary fashion by doing the "long division" of 1 by (1-r) "by hand"...
Could you restate your question a bit more clearly ? Xhat is summed, for what variable ?
What's your formula equal to???
My formula is equal to a/(1-r), for that is for adding a certain sequence to infinity. So now I have to apply to 1/1-(x+x^2)^2.
Do you mean "That" when you type "Xhat"? (to Emmanuel Charpentier)
Anyone could answer me after all?