# Elliptic curve secp-224r1

p=2^224-2^96+1 A=-3#(0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEFFFFFFFFFFFFFFFFFFFFFFE) B=(0xB4050A850C04B3ABF541325650440B7D7BFD8BA270B39432355FFB4)

F=GF(p) E = EllipticCurve( F, [A,B] );E G=E(0xb70e0cbd6bb4bf7f321390b94a03c1d356c21122343280d6115c1d21,0xbd376388b5f723fb4c22dfe6cd4375a05a07476444d5819985007e34);G

the above domain parameter (p,A,B,G) taken from SEC2(standard for efficient cryptography) Recommended Elliptic curve. But when i run the code the error is the point G coordinate do not define point on elliptic curve.

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## Comments

1

To display blocks of code or error messages, skip a line above and below, and do one of the following (all give the same result):

• indent all code lines with 4 spaces
• select all code lines and click the "code" button (the icon with '101 010')
• select all code lines and hit ctrl-K

For instance, typing

If we define f by

def f(x, y, z):
return x * y * z

then f(2, 3, 5) returns 30 but f(2*3*5) gives:

TypeError: f() takes exactly 3 arguments (1 given)


produces:

If we define f by

def f(x, y, z):
return x * y * z


then f(2, 3, 5) returns 30 but f(2*3*5) gives:

TypeError: f() takes exactly 3 arguments (1 given)


Please edit your question to do that.