Class groups of number fields obtained by adding p-torsion points of elliptic curves

tungnt
141 ●2 ●7 ●17

I am a new user. I am very sorry if this question is inappropriate. I would like to test some of my speculations about the arithmetics of number fields obtained by adding p-torsion points of elliptic curves.

More precisely, suppose E is an elliptic curve over $\mathbb{Q}$ of conductor $p$ . Let $L=\mathbb{Q}(E[p])$ , the field obtained by adding all p-torsion points of $E$ . Are there commands in SAGE that allow us to test whether the p-part of $Cl(L)$ is non-trivial?

For cyclotomic fields $\mathbb{Q}(\zeta_p)$ , one can use Kummer's criterion to see whether the p-part of $Cl(\mathbb{Q}(\zeta_p))$ . However, I do not aware of any analogous criterion for $L=\mathbb{Q}(E[p])$ .

Thank you for reading.

answered 6 years ago

dan_fulea
5650 ●5 ●44 ●97

Please give us a special case. So far, try EllipticCurve? to see how ot initialize an elliptic curve in sage. There are many examples. $E[p]$ can be "computed" more or less starting for intsance from the corresponding division_polynomial. For instance:

p = 3

for a in [3..22]:
    print a

    E = EllipticCurve( QQ, [-1, a] )
    P = E.division_polynomial(3)
    L.<a> = NumberField(P)
    Cl_L = L.class_group()

    if p.divides( Cl_L.order() ):

        print "E =", E
        print "RANK ::", E.rank()
        print "P =", P 
        print "L =", L
        print "Cl(L) ~", L.class_group()

        break

The above rudimentary search finds:

E = Elliptic Curve defined by y^2 = x^3 - x + 19 over Rational Field
RANK :: 1
P = 3*x^4 - 6*x^2 + 228*x - 1
L = Number Field in a with defining polynomial 3*x^4 - 6*x^2 + 228*x - 1
Cl(L) ~ Class group of order 15 with structure C15 of Number Field in a with defining polynomial 3*x^4 - 6*x^2 + 228*x - 1

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Thank you very much for your response. I will try to do some experiments using the above codes.

The examples that I have in mind are the the two modular curves $X_0(11)$ and $X_0(17)$ .

tungnt ( 6 years ago )

My computer has run for about 2 hours without any results. I think one particular reason is that the $Gal(L/\mathbb{Q})$ is always $GL_2(F_p)$ -which is already big for p=11 or p=17.

tungnt ( 6 years ago )

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