Ask Your Question
1

Computation of homomorphisms of number fields

asked 2018-01-27 12:24:56 +0100

MadPidgeon gravatar image

Given two number fields, I want to construct a morphism between them. For this I tried to use the hom member-function of the NumberField object as follows:

R.<zeta3> = CyclotomicField(3)
P.<X> = PolynomialRing(R)
K.<gen1> = R.extension(X^3-zeta3)
L.<gen2> = R.extension(X^3-zeta3^2)
print K.gens(), L.gens()
H = K.hom( [gen2,zeta3^2], L )
print H

The help page of hom specifies:

Return the unique homomorphism from self to codomain that sends self.gens() to the entries of im_gens. Raises a TypeError if there is no such homomorphism.

However, instead of TypeError, I get an incomprehensible error:

File "/home/sage/bin/sage2/local/lib/python2.7/site-packages/sage/rings/number_field/number_field.py", line 1670, in _element_constructor_ raise ValueError("Length must be equal to the degree of this number field") ValueError: Length must be equal to the degree of this number field

What am I doing wrong? Is there a better way to define this morphism?

edit retag flag offensive close merge delete

1 Answer

Sort by ยป oldest newest most voted
0

answered 2018-01-27 12:28:32 +0100

vdelecroix gravatar image

You might have misread the description that you copy paste. The arguments of K.hom must be the list of the images of the generators. In your case, there is one generator for K (which is gen1). Even L is an optional argument.

sage: K.hom([gen2])
Relative number field morphism:
  From: Number Field in gen1 with defining polynomial X^3 - zeta3 over its base field
  To:   Number Field in gen2 with defining polynomial X^3 + zeta3 + 1 over its base field
  Defn: gen1 |--> gen2
        zeta3 |--> -zeta3 - 1
edit flag offensive delete link more

Comments

Maybe I should have included this, but at `print K.gens(), L.gens()' sage answers with

(gen1, zeta3) (gen2, zeta3)

so clearly K has two generators, I think? Secondly, how does it decide where to send zeta3? In this case there is little room, but if we take

P.<X> = PolynomialRing(QQ)
R.<s2> = QQ.extension(X^2-2)
K.<s3> = R.extension(X^2-3)
print K.gens()
H = K.hom( [-s3,-s2], K )
print H

this should also give a valid morphism instead of the one returned by K.hom([-s3]) that maps s2 to itself.

MadPidgeon gravatar imageMadPidgeon ( 2018-01-27 12:42:28 +0100 )edit

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account.

Add Answer

Question Tools

Stats

Asked: 2018-01-27 12:24:56 +0100

Seen: 368 times

Last updated: Jan 27 '18