Ask Your Question
1

Morphism between Klein four group and additive abelian group or order 4

asked 2017-12-04 16:57:26 +0100

bd gravatar image

Hi. Let's say I have an ideal class C with structure G := C2 x C2. I want now to construct a morphism phi: G --> C, s.t. phi(g1) = c1 and phi(g2) = c2.

edit retag flag offensive close merge delete

1 Answer

Sort by ยป oldest newest most voted
0

answered 2017-12-05 19:25:13 +0100

dan_fulea gravatar image

updated 2017-12-06 12:04:58 +0100

It is unclear from the context of the question what is C and what is G. So the solution will be given in a special case that worked first for me.

(Using KleinFourGroup() instead of C did not work. The group morphism in the other direction, initialized as we all would expect, did not work. In order to get it, if needed, an explicit python function can be written, which constructs the inverse map as a pedestrian.)

Code:

C.<c1,c2> = AbelianGroup( 2, [2,2] )
print "C is the following group:"
print C
print "\nIts multiplication table is:"
print C.multiplication_table( names='elements' )

F.<u>  = QuadraticField( 2015 )
G      = F.class_group()
g1, g2 = G.gens()
print "G is the following group:"
print G
phi    = AbelianGroupMorphism( C, G, [c1, c2], [g1, g2] )

for c in C.list():
    print "phi maps %s into %s" % ( c, phi(c) )

Results:

C is the following group:
Multiplicative Abelian group isomorphic to C2 x C2

Its multiplication table is:
    *      1    c2    c1 c1*c2
     +------------------------
    1|     1    c2    c1 c1*c2
   c2|    c2     1 c1*c2    c1
   c1|    c1 c1*c2     1    c2
c1*c2| c1*c2    c1    c2     1

G is the following group:
Class group of order 4 with structure C2 x C2 of Number Field in u with defining polynomial x^2 - 2015
phi maps 1 into 1
phi maps c2 into Fractional ideal class (17, u + 3)
phi maps c1 into Fractional ideal class (19, u + 1)
phi maps c1*c2 into Fractional ideal class (5, u)

LATER EDIT:

Here is an other example, it works for a abelian group model G, used as an abstract model for the class group. (I could not make it at the first attempt work with C.permutation_group()...)

R.<X> = PolynomialRing( QQ )
P = X^4 + 14*X^2 + 46
F.<u> = NumberField( P )
print "F is:\n%s" % F
print "Is F a CM field? %s" % F.is_CM()
C = F.class_group( names='c' )
inv = C.invariants()
G = AbelianGroup( len(inv), inv, names='g' )

print "C is:\n%s\nInvariants: %s\n" % ( C, inv )
print "G is:\n%s\n" % G

c0, c1 = C.gens()
g0, g1 = G.gens()

phi    = AbelianGroupMorphism( G, C, [g0, g1], [c0, c1] )
psi    = ( lambda c: [ g for g in G if C(phi(g)) == c ][0] )

for g in G:
    print "phi(%s) = %s" % ( g, phi(g) )
print
for c in C:
    print "psi(%s) = %s" % ( c, psi(c) )

The inverse map is also present. Results:

F is:
Number Field in u with defining polynomial X^4 + 14*X^2 + 46
Is F a CM field? True
C is:
Class group of order 4 with structure C2 x C2 of Number Field in u with defining polynomial X^4 + 14*X^2 + 46
Invariants: (2, 2)

G is:
Multiplicative Abelian group isomorphic to C2 x C2

phi(1) = 1
phi(g1) = Fractional ideal class (13, u - 6)
phi(g0) = Fractional ideal class (11, u - 3)
phi(g0*g1) = Fractional ideal class (2, u)

psi(Trivial principal fractional ideal class) = 1
psi(Fractional ideal class (13, u - 6)) = g1
psi(Fractional ideal class (11, u - 3)) = g0
psi(Fractional ideal class (2, u)) = g0*g1
edit flag offensive delete link more

Comments

Thank you for the fast answer. C is the always the class group of a quartic/sextic CM filed and G is the corresponding abstract group "printed by sage". Yes, I assume that I have to construct the inverse image too.

bd gravatar imagebd ( 2017-12-05 19:53:37 +0100 )edit

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account.

Add Answer

Question Tools

Stats

Asked: 2017-12-04 16:57:26 +0100

Seen: 281 times

Last updated: Dec 06 '17