Ask Your Question

Chain of fields in sage

asked 2017-04-28 14:46:46 -0500

gelatine1 gravatar image

I would like to construct the field Fp(alpha,beta) where alpha is a root of x^p-x-1 (over Fp[x]) and beta is a root of the polynomial x^p-x-alpha^(p-1) (over Fp(alpha)[x]).

I have tried the following



but I think it creates the field F1 well, but it goes wrong for R2... It also feels like there should be a much more straightforward way to do this in sage. What would be the proper way to do this ?

edit retag flag offensive close merge delete

1 answer

Sort by ยป oldest newest most voted

answered 2017-04-28 16:22:33 -0500

dan_fulea gravatar image

Please let me use $u$ and $v$ for the elements of the fields involved.

First solution:

p = 13
R.<U> = PolynomialRing( GF(p) )
F.<u> = GF( p^p, modulus = U^p - U - 1 )
RF.<V> = PolynomialRing( F )
FF.<v> = F.extension( V^p - V - u^(p-1) )

Then FF is the required field.

Second solution.

We can try to construct the last field at once. Let us observe, that the minimal equation satisfied by $x=u^{p-1}=1+1/u$ is: $$ x^p+\dots+x^2+x-1 =0\ . $$ For instance:

sage: (u^(p-1)) . minpoly()
x^13 + x^12 + x^11 + x^10 + x^9 + x^8 + x^7 + x^6 + x^5 + x^4 + x^3 + x^2 + x + 12

(This is my reason for avoiding $x$.)

Indeed: $$ \sum_{1\le k\le p}\left(1+\frac 1u\right)^k = \left(1+\frac 1u\right)\frac{\left(1+\frac 1u\right)^p-1}{\left(1+\frac 1u\right)-1} =\underbrace{\left(1+\frac 1u\right)}_{u^{p-1}}\frac{\left(1^p+\frac 1{u^p}\right)-1}{\left(1+\frac 1u\right)-1} =\frac{u^{p-1}}{u^{p-1}}=1\ . $$ So the code would be:

p = 13
R.<V> = PolynomialRing( GF(p) )
FF.<v> = GF( p^(p*p), modulus = sum( [ (V^p-V)^k for k in [1..p] ] ) - 1 )

u = 1/(v^p-v-1)

The last two lines recover $u$ in the constructed field, we have:

sage: u.minpoly()
x^13 + 12*x + 12
edit flag offensive delete link more


I have to construct a chain like that, with 5 different elements. When i use the extend function for the 4th time it gives "NotImplementedError"...

gelatine1 gravatar imagegelatine1 ( 2017-04-29 08:42:59 -0500 )edit

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account.

Add Answer

Question Tools

1 follower


Asked: 2017-04-28 14:46:46 -0500

Seen: 30 times

Last updated: Apr 28