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Recurrence, for-loop and zero.

asked 2017-04-23 17:09:35 -0500

sssageeee gravatar image

Hello guys! Hope you guys are having a nice day.

I have some problem as follows: I setup some recurrence as follows

def f(j,k):
if k==0:
elif j==0:
return m

And if we calculate

f(1,1), f(2,1), f(1,2), f(2,2)

in sage, then what we get are

4, 35/2, 35/2, 105/2.

However, if we do the for loop as in the below, I found the above results to be zero!!:

for k in range(3):
    for j in range(3):
        (j,k), expVal(j,k)

And the calculation result from the sage is:

((0, 0), 0)

((1, 0), 1)

((2, 0), 2)

((0, 1), 1)

((1, 1), 0)

((2, 1), 0)

((0, 2), 2)

((1, 2), 0)

((2, 2), 0)

And observe the bolded result above... it is weird that the result is zero... Can anyone help me fix this please...

Thank you for any help! Hope you have a nice rest of the day!

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answered 2017-04-23 19:49:59 -0500

nbruin gravatar image


for k in srange(3):
    for j in srange(3):
        print (j,k),f(j,k)

instead. Standard pitfall unfortunately: in python 2, "integer" division is truncating. Normally sage will provide you with "sage" integers for which division produces rational numbers, but if you use "range" then sage doesn't get the chance.

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Thank you so much nbruin. Hope you have a good day!

sssageeee gravatar imagesssageeee ( 2017-04-23 20:20:31 -0500 )edit

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Asked: 2017-04-23 17:09:35 -0500

Seen: 26 times

Last updated: Apr 23