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help on using chain rule in Sage

asked 2017-02-20 01:25:01 -0600

lefthandstander gravatar image

Does anyone have any tips for using Sage to take derivatives of functions of many variables?

For example, if I define

w(x,y) = x^2 + y^2 (say)

and then if I suppose that x and y depend on an independent variable t, the chain rule applies for finding w.diff(t). The only way I found to do this in Sage is

var('t')

x(t) = cos(t) (say)

y(t) = sin(t)

w(x,y) = x^2 + y^2

w.diff(t)

But this isn't really using the chain rule. If I instead try

var('x,y')

(define w again)

(define x and y again)

w.diff(t)

Out: (x,y) |--> 0

Apparently it thinks the derivative is zero because it still thinks x and y are two independent variables where they appear in w, even though you get

x

Out: t |--> cos(t)

and similarly for y. Any suggestions? Thanks.

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answered 2017-02-20 04:04:15 -0600

eric_g gravatar image

What about

sage: var('t u v')
(t, u, v)
sage: x = function('x')(t)
sage: y = function('y')(t)
sage: w(u,v) = u^2 + v^2
sage: diff(w(x,y), t)
2*x(t)*diff(x(t), t) + 2*y(t)*diff(y(t), t)
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Comments

Great! I see that diff(w,t) at the end gives the same behavior I was observing above. Thanks!

lefthandstander gravatar imagelefthandstander ( 2017-02-20 12:58:54 -0600 )edit

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Asked: 2017-02-20 01:25:01 -0600

Seen: 99 times

Last updated: Feb 20