assign function to an existing function
Hi,
Consider the following code:
sage.var('R')
rho = sage.function('rho')(R)
r = rho(R=R).function(R)
Is there a way to assign some function to rho such that r is modified? For instance, if I do:
y = sage.function('y')(R)
rho = sage.desolve(sage.diff(y,R) - y(R), dvar=y, ivar=R, ics=[0,1]).function(R)->R |--> e^R
Then I get:
r(0)->rho(0)
rho(0)->1
So rho is of course modified, but not r.
Thanks!
Martin
Sure, in Python (and hence Sage) you can assign anything to
r. But we would need to see a more specific example. Also, be aware that some commands have a side effect, but returnNone, so you have to be careful about that - for instance, the bare commandshow(plot())might give an empty plot to show, but the actual Python value returned isNone, not what you might be looking for.Thanks! Just updated my question. Any idea?
Ah, this is more of a Python question, which I'll let others answer. By the way, you don't need the
sagebits unless you are importing Sage explicitly in Python. Maybe you are.Thanks! Yes, I prefer python standalone (makes it easier to use other python libraries) with
import sage.all as sage(makes it where each function comes from).