# convert string to list

I have a string of the form, say, '[(1,2),(2,3)]' and want to obtain the list [(1,2),(2,3)] instead.

1

You can use the `eval`

Python function:

```
sage: s='[(1,2),(2,3)]' ; s
'[(1,2),(2,3)]'
sage: type(s)
<type 'str'>
sage: L = eval(s) ; L
[(1, 2), (2, 3)]
sage: type(L)
<type 'list'>
```

Note however that the string is not preparsed, so you will get Python ints, note Sage integers:

```
sage: type(L[0][0])
<type 'int'>
```

To "benefit" from Sage preparsing, you can do:

```
sage: L = eval(preparse(s)) ; L
[(1, 2), (2, 3)]
sage: type(L[0][0])
<type 'sage.rings.integer.Integer'>
```

0

answered
**
2017-01-03 18:10:25 -0600
**

This post is a wiki. Anyone with karma >750 is welcome to improve it.

Thank you very much for your answer! It works if I use the string s. If instead I use my_string (which, on the surface, looks pretty much like s, but was obtained from opening a .sage file containing the string) then I get: TypeError: 'tuple' object is not callable !!

Asked: **
2017-01-03 16:09:51 -0600
**

Seen: **460 times**

Last updated: **Jan 03 '17**

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