How to solve ODE y'' - 4y' + y - x = 0 using rk4?
How to solve ODE y''+y''-4y'+x = 0 using rk4?
asked 2016-09-06 03:29:59 +0100
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How to solve ODE y''+y''-4y'+x = 0 using rk4?
answered 2016-09-06 19:08:22 +0100
This post is a wiki. Anyone with karma >750 is welcome to improve it.
I tryed
# w = y''
# z = y'
var('x, w, z')
desolve_system_rk4( [w , 4*z + x] , [w,z] , ics = [0,1,0], ivar = x, end_points = 10, step = 0.1)
But does no work correty :(
I got a way to solve the differential equation. If wrong please correct;)
To solve this differential equation we must first make a variable substitution to reduce the differential equation for a first order and thus create a system of ODEs. variable change:
w1 = y w2 = y w3 = y '
Thus, deriving the above variables, we have a system of equations of the form:
w1 '= w2 w2 '= f (x, w1, w2) = 4 * w2 + x
desolve_system_rk4([w2, 4*w2 + x ],[w1 , w2], ics = [0,1,0],ivar = x, step = 0.1, end_points = 2)
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Asked: 2016-09-06 03:29:59 +0100
Seen: 428 times
Last updated: Sep 06 '16
This looks like homework. If you want some help, you should ask more precise questions related to your research in solving those exercises, especially where you are locked.