Ask Your Question

Displaying large prime numbers as 10^a + x?

asked 2016-08-24 18:40:27 -0500

sagemath1993 gravatar image

updated 2016-08-24 19:09:55 -0500

I just started using SAGE and I wanted to display my large prime numbers as 10^a + x, rather than it having it spit out a ton of zeros.

So far my code looks like

P= next_prime(10^a);
next_prime(P)- next_prime(10^a);

With this, it outputs the very large number and while I know how to write it down as 10^a + x (in this case, 10^100 + 949), how do I add that to the code so it would display it like that?

edit retag flag offensive close merge delete

1 answer

Sort by ยป oldest newest most voted

answered 2016-08-24 20:12:37 -0500

updated 2016-08-24 20:27:17 -0500

One simple way is to use a formatted Python string like

'10^{} + {}'.format(a,difference)

Here's some code that prints the decomposition of the first five primes above 10^a:

a = 100
p = 10^a

for i in range(0,5):
    p = next_prime(p)
    print( '10^{} + {}'.format(a, p - 10^a) )

and here's a live example.

edit flag offensive delete link more


Thank you! It seems my code is displaying the 2nd prime and the difference between the 2nd and 1st prime after 10^a instead of displaying the first prime after 10^a

sagemath1993 gravatar imagesagemath1993 ( 2016-08-24 20:43:09 -0500 )edit

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account.

Add Answer

Question Tools


Asked: 2016-08-24 18:40:27 -0500

Seen: 36 times

Last updated: Aug 24 '16