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How to return a list from a recursive function?

asked 2016-07-27 18:09:54 -0500

anonymous user

Anonymous

updated 2016-07-27 20:12:32 -0500

Hello,

I am trying to make a recursive function that will return a list but I get a SyntaxError. Here is the code working so far (just an example):

def myfactorial(n):
    if n == 1: 
        return 1
    else: 
        return n * myfactorial(n-1)

myfactorial(10)

I need to return something like this: [1, 1, 2, 6, 24, 120, 720, 5040, 40320, 362880]

I know that there is already a build in factorial function, I created this recursive function only as an example of what I am trying to get: a list. To return a list of all values of a given recursion, the steps of it...

[myfactorial(n) for n in range(1, 10)]

    [1, 2, 6, 24, 120, 720, 5040, 40320, 362880]

Now, how to put it "inside" in the recursive function?

Thank you for your attention.

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answered 2016-07-28 02:26:25 -0500

mforets gravatar image
def myfactorial(n):
    if n == 1: 
        return [1]
    else: 
        return myfactorial(n-1) + [n * myfactorial(n-1)[n-2]]
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Asked: 2016-07-27 18:09:54 -0500

Seen: 45 times

Last updated: Jul 28 '16