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Define a function with different cases

asked 2016-04-12 17:20:01 -0600

Massimo2013 gravatar image

I'm working with a function whose functional form is different at a specific value of the parameter (a=1):

 if a==1:
            U(x,L)=log(x)+log(1-L)
 else:
            U(x,L)=(x^(1-a)/(1-a)+(1-L)^(1-a)/(1-a))

Is it possible to define once and for all a function U(x,L,a) which includes the parameter as a variable so that I don't need to redefine it when a = 1?

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answered 2016-04-13 09:23:08 -0600

calc314 gravatar image

You can create a Python function which does this as follows:

def U(x,L,a):
    if a==1:
            return(log(x)+log(1-L))
    else:
            return(x^(1-a)/(1-a)+(1-L)^(1-a)/(1-a))
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Asked: 2016-04-12 17:20:01 -0600

Seen: 74 times

Last updated: Apr 13 '16