Define a function with different cases

asked 2016-04-13 00:20:01 +0100

Massimo2013
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I'm working with a function whose functional form is different at a specific value of the parameter (a=1):

 if a==1:
            U(x,L)=log(x)+log(1-L)
 else:
            U(x,L)=(x^(1-a)/(1-a)+(1-L)^(1-a)/(1-a))

Is it possible to define once and for all a function U(x,L,a) which includes the parameter as a variable so that I don't need to redefine it when a = 1?

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answered 2016-04-13 16:23:08 +0100

calc314
4191 ●22 ●48 ●113

You can create a Python function which does this as follows:

def U(x,L,a):
    if a==1:
            return(log(x)+log(1-L))
    else:
            return(x^(1-a)/(1-a)+(1-L)^(1-a)/(1-a))

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Asked: 2016-04-13 00:20:01 +0100

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Last updated: Apr 13 '16

Define a function with different cases edit

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