Define a function with different cases

First time here? Check out the FAQ!

Massimo2013
71 ●4 ●6 ●10

I'm working with a function whose functional form is different at a specific value of the parameter (a=1):

 if a==1:
            U(x,L)=log(x)+log(1-L)
 else:
            U(x,L)=(x^(1-a)/(1-a)+(1-L)^(1-a)/(1-a))

Is it possible to define once and for all a function U(x,L,a) which includes the parameter as a variable so that I don't need to redefine it when a = 1?

add a comment

1 Answer

Sort by » oldest newest most voted

answered 8 years ago

calc314
4191 ●22 ●48 ●113

You can create a Python function which does this as follows:

def U(x,L,a):
    if a==1:
            return(log(x)+log(1-L))
    else:
            return(x^(1-a)/(1-a)+(1-L)^(1-a)/(1-a))

link

add a comment

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account.

Add Answer

Question Tools

1 follower

Stats

Asked: 8 years ago

Seen: 731 times

Last updated: Apr 13 '16

Define a function with different cases savecancel

1 Answer

Your Answer

Question Tools

Stats

Related questions