Ok, I'm encountering this weird result when performing:
l = [2, 5, 2, 6, 7, 3, 7, 5, 7, 0, 6, 10]
r = median(l)
The r becomes 11/2 which is 5.5. The median here is clearly an integer and it is 5!
Why does it return 5.5?
if hasattr(v, 'median'): return v.median()
if len(v) == 0:
# Median of empty set defined as NaN
return NaN
values = sorted(v)
if len(values) % 2 == 1:
return values[((len(values))+1)/2-1]
else:
lower = values[(len(values)+1)/2-1]
upper = values[len(values)/2]
return (lower + upper)/ZZ(2)
For completeness: "If there is an even number of observations, then there is no single middle value; the median is then usually defined to be the mean of the two middle values..." see https://en.wikipedia.org/wiki/Median
How do you guys read the answer? I don't understand this. I am new to this website.
Asked: 2015-07-10 20:56:30 +0100
Seen: 7,820 times
Last updated: Jul 23 '15
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The list has length 12 (even). I think what sage is returning is the average of elements at positions 6 and 7, which are 5 and 6.