# How do I adjust the position of my figure's title and remove the extra set of coordinates shown?

I tried to solve this problem myself (http://ask.sagemath.org/question/2680...) using this code (which itself is largely copied from http://ask.sagemath.org/answers/15011...):

```
from sage.calculus.desolvers import desolve_odeint
y,dy = var('y,dy');
g = 9.8;
l = 1;
f = [dy,-g/l*cos(y)];
v = [y,dy];
t = srange(0,5,0.01);
ci = [0,0];
sol = desolve_odeint(f,ci,t,v,rtol=1e-15, atol=1e-10,h0=1e-4,hmax=1e-2,hmin=1e-6,mxstep=10000)
p = line(zip(t,sol[:,0]));
p2 = line(zip(t,sol[:,1]));
import matplotlib as mpl
import matplotlib.pyplot as plt
from mpl_toolkits.axes_grid.axislines import SubplotZero
def mplot(sage_plot, equal_scale = False, edit_res = False):
"""
This function convert sage_plot, created at sage, in matplotlib graph.
"""
plt.clf()
fig = plt.figure()
plt.xlabel(r"$t$")
plt.ylabel(r"$\theta$")
plt.title(r"$\frac{d^{2}\theta}{dt^2} = -\frac{g}{l} \cos{\theta}$")
ax = SubplotZero(fig, 111)
fig.add_subplot(ax)
L = sage_plot.matplotlib().gca().lines
for t in L:
data = t.get_data()
ax.add_line(mpl.lines.Line2D(data[0], data[1]))
ax.autoscale_view()
if equal_scale:
ax.axis('equal')
for direction in ["xzero", "yzero"]:
ax.axis[direction].set_axisline_style("-|>", size = 2)
ax.axis[direction].set_visible(True)
for direction in ["left", "right", "bottom", "top"]:
ax.axis[direction].set_visible(False)
ax.axis["yzero"].set_axis_direction("right")
ax.minorticks_on()
ax.grid()
if edit_res:
return(fig)
else:
plt.savefig('')
plt.close()
mplot(p,equal_scale = True)
```

but it gives this output: .

My problem with this plot is that the title (i.e., the differential equation) is partially cut off and for some reason there's two alternate numbering schemes along the x and axis (two set from 0 to 1, the others being the real x & y coordinates which go from -pi to 0)