Ask Your Question
0

Solve a system of nonlinear equations

asked 2015-05-06 20:26:34 +0200

Massimo2013 gravatar image

I'm trying to solve the following system of nonlinear equation:

var("x,L,a")
sms = (x/(1-L))^(1-a) == .3
bb = x == .3*L
solve([sms,bb],x,L)

I expect that sage gives me a symbolic solution, the output is the following:

[x == 0.3*L, (-x/(L - 1))^(-a + 1) == 0.3]

As I am a newbie to sage, I wonder if there's something wrong/missing

edit retag flag offensive close merge delete

1 Answer

Sort by ยป oldest newest most voted
0

answered 2015-05-07 03:55:39 +0200

calc314 gravatar image

Since bb is fairly simple, you can substitute that into sms. Then, solving gives something nice. However, you have to tell Sage some information about a.

var("x,L,a")
assume(a>0)
assume(a<1)
sms = (x/(1-L))^(1-a) == 3/10
bb = x == 3/10*L
solve(sms.subs(bb),L)
edit flag offensive delete link more

Comments

I have a similar problem where my version of bb is not so simple and (sms == sms.subs(bb)) is true. Does a different method exist to solve the problem?

Johan gravatar imageJohan ( 2016-05-18 15:08:39 +0200 )edit

I suggest creating a separate post and giving some example code so we can see exactly what you are working with.

calc314 gravatar imagecalc314 ( 2016-05-18 22:15:41 +0200 )edit

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account.

Add Answer

Question Tools

Stats

Asked: 2015-05-06 20:26:34 +0200

Seen: 729 times

Last updated: May 07 '15