A confusing syntax error when using elif

asked 2015-04-14 18:04:19 +0100

Haron
13 ●1 ●1 ●4

Dear All

This is my confusing problem:

sage: m=31
sage: if m%3==0:
....:     print m/3
....:     elif m%3==1:
....:         print (m-1)/3
....:
File "<ipython-input-2-ec9f38b42615>", line 3
  elif m%Integer(3)==Integer(1):
      ^
SyntaxError: invalid syntax

sage:

I do not copy-paste the code. I have ubuntu14.04 and my sage version is 6.5.

answered 2015-04-14 18:12:28 +0100

Nathann
1615 ●2 ●15 ●36

The 'elif' should not be inside of the 'if'

http://www.tutorialspoint.com/python/...

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Comments

Thank you. I understand.

Haron ( 2015-04-14 18:27:19 +0100 )edit

@Haron - if this completely answered your question, please don't forget to "accept" by clicking the check mark, so that people coming to this site with the same question know they will find an answer. Thanks!

kcrisman ( 2015-04-14 20:27:14 +0100 )edit

@kcrisman Thank you Kcrisman. Sorry for this delaying.

Haron ( 2015-04-15 20:07:28 +0100 )edit

No problem, just a reminder for future visitors - glad Nathann could help!

kcrisman ( 2015-04-15 20:17:28 +0100 )edit

That is the person who gave you this answer :)

kcrisman ( 2015-04-15 22:49:44 +0100 )edit

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