# Solving system of linear Diophantine equations

I have an $m \times n$ integer matrix $A$ with $m>n$, and a set $S \subset \mathbb{Z}$, for example $S=\{-1,0,1\}$.

I want to enumerate all possible $X \in S^n$ such that $AX=0$.

I tried using smith_form(), but then i could not figure out how to force the solution to belong to elements of $S$.

EDIT. Thank you Dima for the solution. It works well. I am adding an example here to illustrate your solution.

```
lb = -1
ub = 1
A = matrix(ZZ, [(8,2,10,0,12,2,0), (4,6,9,1,14,5,2), (2,0,1,1,0,1,0), (2,1,3,0,4,0,1)])
eq1 = [(0,8,2,10,0,12,2,0), (0,4,6,9,1,14,5,2), (0,2,0,1,1,0,1,0), (0,2,1,3,0,4,0,1)]
ieq1 = [(-lb,1,0,0,0,0,0,0), (ub,-1,0,0,0,0,0,0),
(-lb,0,1,0,0,0,0,0), (ub,0,-1,0,0,0,0,0),
(-lb,0,0,1,0,0,0,0), (ub,0,0,-1,0,0,0,0),
(-lb,0,0,0,1,0,0,0), (ub,0,0,0,-1,0,0,0),
(-lb,0,0,0,0,1,0,0), (ub,0,0,0,0,-1,0,0),
(-lb,0,0,0,0,0,1,0), (ub,0,0,0,0,0,-1,0),
(-lb,0,0,0,0,0,0,1), (ub,0,0,0,0,0,0,-1)]
p = Polyhedron(eqns=eq1, ieqs=ieq1, base_ring=QQ)
p.integral_points()
```

returns the answer

```
((-1, -1, 1, 1, 0, 0, 0),
(0, -1, -1, 1, 1, 0, 0),
(0, -1, 0, -1, 0, 1,1),
(0, 0, 0, 0, 0, 0, 0),
(0, 1, 0, 1, 0, -1, -1),
(0, 1, 1, -1, -1, 0,0),
(1, 1, -1, -1, 0, 0, 0))
```

which is exactly what i needed. Thanks again.