checking left hand side of an equation

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jeanpat
53 ●4 ●6 ●11

Hi, I'd like to check if the operation applied to an equation yields the solution as follow: a=var('a') eq= a+7==6

print eq.lhs()
LHS =(eq-7).lhs()
print LHS
LHS==a
a is a
LHS is a

I was waiting that the line LHS==a yields True or False. How can I check that LHS contains the variable a?

edit

`LHS is a`

yields False

1 Answer

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The problem here is that, since LHS is a symbolic expression, then LHS == a will also be a symbolic expression, not a boolean, see:

sage: LHS.parent()
Symbolic Ring
sage: (LHS == a).parent()
Symbolic Ring

You can try:

sage: bool(LHS == a)
True

Also, LHS is a yields to False since LHS and a do not point to the same object in memory.

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Last updated: Jan 03 '14