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is exist a field is FunctionField() but not RationalFunctionField()?

asked 2013-12-23 04:55:36 +0200

cjsh gravatar image

updated 2013-12-25 00:57:53 +0200

is exist a field is FunctionField() but RationalFunctionField()?

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answered 2013-12-23 06:20:15 +0200

tmonteil gravatar image

I am not sure i understand your question, but FunctionField() creates a rational funciton field (from which you can create other function fields), see this page;

sage:  K.<x> = FunctionField(RDF)
sage: K
Rational function field in x over Real Double Field
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answered 2013-12-23 07:17:08 +0200

cjsh gravatar image

from sage.rings.function_field.function_field import is_FunctionField



from sage.rings.function_field.function_field import is_RationalFunctionField

Traceback (click to the left of this block for traceback) ... ImportError: cannot import name is_RationalFunctionField

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answered 2013-12-23 07:11:43 +0200

cjsh gravatar image

updated 2013-12-23 07:17:45 +0200

thank you very much!

I donot know other function fields not RationalFunctionField,cound give more?

Real Field is not a RationalFunctionField? is there a polynomial?

F(RR)(t),even F(CC)(t) is p-adic,whether F(Qp)(t) is a RationalFunctionField?

there a word name totally_positive in Real Field ,and there a function named is_totally_positive() in Global Number Fields,the same meaning?

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Asked: 2013-12-23 04:55:36 +0200

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Last updated: Dec 25 '13