Ask Your Question
0

is exist a field is FunctionField() but not RationalFunctionField()?

asked 2013-12-22 21:55:36 -0500

cjsh gravatar image

updated 2013-12-24 17:57:53 -0500

is exist a field is FunctionField() but RationalFunctionField()?

edit retag flag offensive close merge delete

3 answers

Sort by ยป oldest newest most voted
1

answered 2013-12-22 23:20:15 -0500

tmonteil gravatar image

I am not sure i understand your question, but FunctionField() creates a rational funciton field (from which you can create other function fields), see this page;

sage:  K.<x> = FunctionField(RDF)
sage: K
Rational function field in x over Real Double Field
edit flag offensive delete link more
0

answered 2013-12-23 00:11:43 -0500

cjsh gravatar image

updated 2013-12-23 00:17:45 -0500

thank you very much!

I donot know other function fields not RationalFunctionField,cound give more?

Real Field is not a RationalFunctionField? is there a polynomial?

F(RR)(t),even F(CC)(t) is RationalFunctionField.like p-adic,whether F(Qp)(t) is a RationalFunctionField?

there a word name totally_positive in Real Field ,and there a function named is_totally_positive() in Global Number Fields,the same meaning?

edit flag offensive delete link more
0

answered 2013-12-23 00:17:08 -0500

cjsh gravatar image

from sage.rings.function_field.function_field import is_FunctionField

is_FunctionField(RDF)

False

from sage.rings.function_field.function_field import is_RationalFunctionField

Traceback (click to the left of this block for traceback) ... ImportError: cannot import name is_RationalFunctionField

edit flag offensive delete link more

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account.

Add Answer

Question Tools

Stats

Asked: 2013-12-22 21:55:36 -0500

Seen: 76 times

Last updated: Dec 24 '13