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Substitute x value in a linear regression equation instead of writing it out?

asked 2013-06-26 06:35:12 -0600

bxdin gravatar image

updated 2013-06-26 08:27:46 -0600

tmonteil gravatar image

Thanks to this handy post, I was able to generate a linear regression graph: http://stackoverflow.com/questions/45...

My input thus far in sage 5.9:

r = [[0,76.4], [1,78.5], [2,81.5], [3,87.8], 
     [4,88.4], [5,92.4], [6,94.0], [7,95.0]]
var('a,b')
(a, b)    #It seems this statement is extraneous
model(x) = a*x+b
find_fit(r, model)
plot(model(a = find_fit(r, model)[0].rhs(), 
           b = find_fit(r,model)[1].rhs()), 
           0,15, ymin = 0, ymax = 150)

What would be the most practical way of substituting the x value to generate an answer instead of:

Executing: find_fit(r, model) Then copying and pasting the answer: [a == 2.8690476152412128, b == 76.70833334665576]

And then having to manually write out, where number 15 represents what I wanted to put substitute for x: 2.8690476152412128 * (15) + 76.70833334665576

Also 1 of my other threads has an unsolved question, incase anyone's interested: http://ask.sagemath.org/question/2732...

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BTW, you are right that the `(a,b)` is extraneous - that's showing the *output* if you do this in the command line.

kcrisman gravatar imagekcrisman ( 2013-06-26 07:20:55 -0600 )edit

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answered 2013-06-26 06:47:54 -0600

tmonteil gravatar image

updated 2013-06-26 06:48:44 -0600

I am not sure to understand your question. Does the following answer it ?

sage: sol = find_fit(r, model)
sage: A,B = (sol[0].rhs(), sol[1].rhs())
sage: f(x) = model.subs(a=A, b=B) ; f
x |--> 2.8690476190478367*x + 76.70833333333225
sage: f(15)
119.74404761904981
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Thanks :D.

bxdin gravatar imagebxdin ( 2013-06-26 11:08:33 -0600 )edit

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Asked: 2013-06-26 06:35:12 -0600

Seen: 647 times

Last updated: Jun 26 '13