# basis of hyperplane

Hallo

I am new to sage and have this problem.

Given a hyperplane $H_u \subset GF(2^{n+1})$ define by $x |-> a^8 +a$

How do I determine the basis of $H_u$ over $GF(2)$?

Regards

basis of hyperplane

Hallo

I am new to sage and have this problem.

Given a hyperplane $H_u \subset GF(2^{n+1})$ define by $x |-> a^8 +a$

How do I determine the basis of $H_u$ over $GF(2)$?

Regards

add a comment

1

I do not understand how the constant map $x\mapsto a^8+a$ defines a hyperplane, but if you want to find a basis of the orthogonal hyperplane of the vector $a^8+a$, where $a$ is "the" generator of $K = GF(2^{n+1})$ viewed as a vector space over $F = GF(2)$, you can:

```
sage: n = 6
sage: K = GF(2^(n+1),'a') ; K
Finite Field in a of size 2^7
sage: a = K.gen()
sage: F = K.base() ; F
Finite Field of size 2
sage: V = K.vector_space() ; V
Vector space of dimension 7 over Finite Field of size 2
sage: v = V(a^8 + a) ; v
(0, 0, 1, 0, 0, 0, 0)
sage: m = matrix(v) ; m
[0 0 1 0 0 0 0]
sage: m.right_kernel().basis()
[
(1, 0, 0, 0, 0, 0, 0),
(0, 1, 0, 0, 0, 0, 0),
(0, 0, 0, 1, 0, 0, 0),
(0, 0, 0, 0, 1, 0, 0),
(0, 0, 0, 0, 0, 1, 0),
(0, 0, 0, 0, 0, 0, 1)
]
```

@tmonteil, thanx the map was suppose to be $x\mapsto x\cdot a^8 + x^8 \cdot a$. By adding the code f = lambda x: x * a^8 + a * x^8 S = V.subspace([f(x) for x in K]) S.basis() I got a solution. What will the most effective method to create a map (isomorphism) from $S$ to $GF(2^n)$?

Asked: **
2013-07-20 09:40:54 -0600
**

Seen: **1,007 times**

Last updated: **Jul 20 '13**

Yet another linear combination

Row reduction modulo prime powers

A way of checking that a multivariate system of equations has a solution?

Does anyone know how to implement a simple XL Algorithm in sage?

How does one detect cyclic vectors in SAGE?

linear algebra point and line [closed]

How to stop Sage from finding erroneous complex roots?

Newbie question: introducing symbols (variables) inside vectors and matrices

Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.