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I am trying to solve recurring deposite equation but answer is another equation,please help

asked 2013-05-31 23:31:31 -0600

sagesup gravatar image

Following is the problem I am trying to solve


x = var('x')
solve(10000*(1+(0.0825/4))^(x*4)==400000,x)
 

but instead of value of x I am getting


[1633^x == I*40^(1/4)*1600^x, 1633^x == -40^(1/4)*1600^x, 1633^x == -I*40^(1/4)*1600^x, 1633^x == 40^(1/4)*1600^x]
 

Please advise how to solve this!

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answered 2013-06-01 00:36:39 -0600

tmonteil gravatar image

updated 2013-06-01 00:37:47 -0600

What kind of solution do you need (symbolic, numerical, real, complex, ...) ?

If you want a numerical approximation of the unique real solution, you ca try:

sage: f(x) = 10000*(1+(0.0825/4))^(x*4) - 400000
sage: f.find_root(40,50)
45.17323135481834
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Asked: 2013-05-31 23:31:31 -0600

Seen: 152 times

Last updated: Jun 01 '13