ASKSAGE: Sage Q&A Forum - RSS feedhttps://ask.sagemath.org/questions/Q&A Forum for SageenCopyright Sage, 2010. Some rights reserved under creative commons license.Fri, 20 Sep 2013 15:56:30 +0200Dome with a parabolic shape?https://ask.sagemath.org/question/10530/dome-with-a-parabolic-shape/This is my last question for today!! Usually I'm good at math, but I've been sick for over a year and am now finding it hard to concentrate. :P Here is the question:
The dome over a town hall has a parabolic shape. The dome measures 48 m across and rises 12 m at its centre.
a) Determine the quadratic equation that models the shape of the dome.
I already did this and here is my answer. Please correct me if I'm wrong. :)
First Zero:
(0,0)
x1 = 0
Second Zero:
(48,0)
x2 = 48
Determining the location of the axis of symmetry:
x1 + x2 / 2
= 0 + 48 / 2
= 48 / 2
= 24
Therefore, the location of the axis of symmetry is x = 24.
b) A vertical column needs to be attached to the dome at a point that is 4 m away from its rim. How tall is the dome at this point?
I tried solving this but got lost.
c) The dome sits on top of the town hall, which is 20 m high. How high does the column have to be, to reach from the floor to the dome?
I did not get to that one because I know I need information from the other two questions in order to solve this. :P
Thank-you so much!
MadyminoFri, 20 Sep 2013 15:56:30 +0200https://ask.sagemath.org/question/10530/