ASKSAGE: Sage Q&A Forum - Latest question feedhttp://ask.sagemath.org/questions/Q&A Forum for SageenCopyright Sage, 2010. Some rights reserved under creative commons license.Mon, 13 Nov 2017 21:57:15 -0600Exterior algebra errorhttp://ask.sagemath.org/question/39523/exterior-algebra-error/Hi,
I'm new to Sage, and I've been having a lot of trouble constructing a particular algebra. I want to construct the exterior algebra (over $\mathbb{Q}$) on generators $w_{i,j} = w_{j,i}$ where $1 \le i < j \le n$ for some $n$ (for concreteness, say $n = 6$). I want this particular generating set so that I can define an $S_n$ action, but that's the next challenge. I've been attempting the following rough outline:
1. Construct a vector space $V \cong \mathbb{Q}^n$, with basis $\{v_i\}$.
2. Take a tensor product $V \otimes V$, with basis $w_{i,j} = v_i \otimes v_j$.
3. Take a quotient to impose relations $w_{i,i} = 0$ and $w_{i,j} = w_{j,i}$.
4. Take the exterior algebra on the quotient.
Several possible data structures for $V$ (FiniteRankFreeModule, VectorSpace, FreeModule) seem to fail at step 2. Are tensor products implemented for these? The most promising structure, CombinatorialFreeModule, fails at step 4 for an unknown reason. I get an error "base must be a ring or a subcategory of Rings()", even though the base is $\mathbb{Q}$.
Here's the specific code I've tried.
indices = range(1,7)
V = CombinatorialFreeModule(QQ, indices)
V2 = tensor((V,V))
w = V2.basis()
relations = []
for i in indices:
relations.append(w[i,i])
for j in range(i+1,7)
relations.append(w[i,j] - w[j,i])
R = V2.submodule(relations)
V3 = V2.quotient_module(R)
A = ExteriorAlgebra(V3)
The last line gives an error, "base must be a ring or a subcategory of Rings()". The command `V2.base() in Rings()` returns true, but I can't get around the error.
Any help would be appreciated, either in fixing this error or approaching the construction in a different way.Nat MayerMon, 13 Nov 2017 21:57:15 -0600http://ask.sagemath.org/question/39523/