ASKSAGE: Sage Q&A Forum - Latest question feedhttp://ask.sagemath.org/questions/Q&A Forum for SageenCopyright Sage, 2010. Some rights reserved under creative commons license.Sat, 28 Feb 2015 17:27:40 -0600dividing vector(a,b) by sqrt(x) gives (a/x*sqrt(x),b/x*sqrt(x))http://ask.sagemath.org/question/25980/dividing-vectorab-by-sqrtx-gives-axsqrtxbxsqrtx/ I can't seem to figure out why the behavior above is happening.
I have been trying to familiarize myself with Sage as I am both an IT person at my university and currently a Calc III student and it would seem to me to be helpful for both to know how this software works since many professors use it and I can use it to check work in my classes.
When I attempt to get the unit vector in the direction of <1,1> I divide the vector by its magnitude, and instead of the expected result of <1/sqrt(2), 1/sqrt(2)> I have been getting <1/2*sqrt(2), 1/2*sqrt(2)> and this happens the same way with a vector divided by the sqrt of anything. (i.e. <1,1> / sqrt(3) == <1/3*sqrt(3), 1/3*sqrt(3)>)
Is this a bug, or am I missing something?
EDIT - To clarify, I am dividing a vector by it's magnitude, which is a scalar number. vector{a,b} divded by c should yield vector{a/c, b/c}. This works fine for integers. but when doing so with the sqrt() function it produces odd results. So if c == sqrt(d) the answer is coming back as vector{a/(d*c), b/(d*c)} and I don't understand why the denominator is being multiplied by d.
RickySat, 28 Feb 2015 17:27:40 -0600http://ask.sagemath.org/question/25980/