ASKSAGE: Sage Q&A Forum - RSS feedhttps://ask.sagemath.org/questions/Q&A Forum for SageenCopyright Sage, 2010. Some rights reserved under creative commons license.Wed, 26 Jun 2013 13:35:12 +0200Substitute x value in a linear regression equation instead of writing it out?https://ask.sagemath.org/question/10286/substitute-x-value-in-a-linear-regression-equation-instead-of-writing-it-out/Thanks to this handy post, I was able to generate a linear regression graph:
http://stackoverflow.com/questions/454606/how-can-i-do-regression-analysis-in-sage
My input thus far in sage 5.9:
r = [[0,76.4], [1,78.5], [2,81.5], [3,87.8],
[4,88.4], [5,92.4], [6,94.0], [7,95.0]]
var('a,b')
(a, b) #It seems this statement is extraneous
model(x) = a*x+b
find_fit(r, model)
plot(model(a = find_fit(r, model)[0].rhs(),
b = find_fit(r,model)[1].rhs()),
0,15, ymin = 0, ymax = 150)
What would be the most practical way of substituting the x value to generate an answer instead of:
Executing: find_fit(r, model)
Then copying and pasting the answer: [a == 2.8690476152412128, b == 76.70833334665576]
And then having to manually write out, where number 15 represents what I wanted to put substitute for x: 2.8690476152412128 * (15) + 76.70833334665576
Also 1 of my other threads has an unsolved question, incase anyone's interested:
http://ask.sagemath.org/question/2732/display-y-interceptbxdinWed, 26 Jun 2013 13:35:12 +0200https://ask.sagemath.org/question/10286/