ASKSAGE: Sage Q&A Forum - Latest question feedhttp://ask.sagemath.org/questions/Q&A Forum for SageenCopyright Sage, 2010. Some rights reserved under creative commons license.Wed, 03 Dec 2014 18:07:57 -0600Solving systems of equations always returns [ ]http://ask.sagemath.org/question/25105/solving-systems-of-equations-always-returns/Suppose I have the set of equations and I'm trying to solve for f1, f2 and f3:
![formula][1]
[1]: http://latex.codecogs.com/gif.latex?f_1%20%26%3D%26%20a+b+f_2%20%5C%5C%202f_2%20%26%3D%26%20c+d+f_1%20%5C%5C%20f_3%20%26%3D%26%20f_1+f_2
I've tried solving it in the following way
eq1 = f1 == a + b + f2
eq2 = 2*f2 == c + d + f1
eq3 = f3 == f1 + f2
solve([eq1,eq2,eq3],f1,f2,f3)
[]
This is easy to solve using matrices, and I have double-checked that the answer is fully constrained, so why does sage always return [ ]? I would have expected answers for f1, f2 and f3 in terms of a, b , c and d. Is there another argument to solve() that tells Sage what I want my answer in terms of?
I would prefer to use solve() instead of matrices both for the sake of convenience and if I have a nonlinear system later on.
EvidloWed, 03 Dec 2014 18:07:57 -0600http://ask.sagemath.org/question/25105/