ASKSAGE: Sage Q&A Forum - Latest question feedhttp://ask.sagemath.org/questions/Q&A Forum for SageenCopyright Sage, 2010. Some rights reserved under creative commons license.Mon, 15 Oct 2012 12:15:30 -0500Finding solution to nonlinear equations numerically in a rangehttp://ask.sagemath.org/question/9430/finding-solution-to-nonlinear-equations-numerically-in-a-range/Hi,
this question is probably quite easy to solve. I've got two nonlinear equations with a solution in the range of (0,1). As described in the sage tutorial I tried the following:
var('p t')
eq2 = p==1 - (1 - (1 - (1 - 0.01)^1036)^20)*(1 - t)^(9)
eq1 = t==(2*(1 - 2*p))/((1 - 2*p)*16 + 15*p(1 - (2*p)^1023))
solns = solve([eq1,eq2],t, solution_dict=True)
[[s[t].n(10)] for s in solns]
Unfortunately this doesn't work. In addition I tried find_root, but failed miserably. Any ideas? rnwW6Qz3Mon, 15 Oct 2012 12:15:30 -0500http://ask.sagemath.org/question/9430/