ASKSAGE: Sage Q&A Forum - Latest question feedhttps://ask.sagemath.org/questions/Q&A Forum for SageenCopyright Sage, 2010. Some rights reserved under creative commons license.Wed, 16 Nov 2016 05:12:07 -0600Particular solve: find values of variables which will solve equation for any values of other variableshttps://ask.sagemath.org/question/35609/particular-solve-find-values-of-variables-which-will-solve-equation-for-any-values-of-other-variables/ Hi, this is my first time using Sage, so I hope my questions aren't too trivial.
I have to solve the following problem: find (if they exist) values of real variables x,u,v (with x,v>0) such that the following equality
Maximum{2 a/x, 2 (u*b + v*c)/(u^2 + v^2),
2 ((u - x)*(b - a) + v*c)/(v^2 + (u - x)^2)} = (a/x + c/v) + (1/v*x)*sqrt(
a^2 (u^2 + v^2) - 2 a*x*(b*u + c*v) + (b^2 + c^2)*x^2)
is verified for every value of the real values a, b, c.
It is my understanding that to evaluate the maximum I should use max_symbolic, am I right?
Let me emphasize that I don't need to find values of x,u,v with respect to a,b,c, but fixed values of x,u,v which will verify the equality for any given a,b,c. This means that I need to find x, u, v which will verify all the infinite equations we will get for any different triple of values of a, b, c.
For this reason writing
x,u,v,a,b,c=var('x u v a b c')
s1=solve([max_symbolic(2 a/x, 2*(u*b + v*c)/(u^2 + v^2), 2 ((u - x)*(b - a) + v*c)/(v^2 + (u - x)^2)) == (a/x + c/v) +(1/v*x)*sqrt(a^2 (u^2 + v^2) - 2 a*x*(b*u + c*v) + (b^2 + c^2)*x^2)],x,u,v)
show(s1)
will not work. I've thought of solving for all 6 variables, but then an error occurred saying solve() could only use 5 positional arguments..
Can you suggest me any way to proceed? Also, I fear this kind of computation will be very heavy for my cpu.. Any ideas on how to make It lighter?
Thank you very much!nibWed, 16 Nov 2016 05:12:07 -0600https://ask.sagemath.org/question/35609/