ASKSAGE: Sage Q&A Forum - Latest question feedhttp://ask.sagemath.org/questions/Q&A Forum for SageenCopyright Sage, 2010. Some rights reserved under creative commons license.Fri, 06 Apr 2018 12:33:52 -0500temp22.sobj is not UTF-8 encodedhttp://ask.sagemath.org/question/41890/temp22sobj-is-not-utf-8-encoded/I get a temp22.sobj is not UTF-8 encoded after trying to open this file
I saved by using save(G.allsimplecycles, 'temp22') what am I doing wrong?
standardtrickynessFri, 06 Apr 2018 12:33:52 -0500http://ask.sagemath.org/question/41890/How to get an arbitrary orientation of a graph.http://ask.sagemath.org/question/9835/how-to-get-an-arbitrary-orientation-of-a-graph/**I'VE COMPLETELY REVISED MY QUESTION**
I wish to take a simple undirected graph (i.e. the complete graph K_4)
Arbitrarily direct said graph, and then create a line graph from the directed version of the graph.
However, in Sage it appears to create a line graph that shows a connection between two edges (that are just inverses of each other), so what I really want is a line graph that doesn't give an edge connected to its own inverse.
**That's why I asked if we could remove cycles of length 2, but that doesn't seem to solve the problem.**
Here's what I am trying to work out:
G = graphs.RandomGNP(4,1)
GD = G.to_directed() #orients G
m = GD.size() #number of edges of digraph GD
LG = GD.line_graph() #the line graph of the digraph
IM = identity_matrix(QQ,GD.size())
T = LG.adjacency_matrix()#returns the adjacency matrix of the line graph
var('u') #defines u as a variable
X=IM-u*T #defines a new matrix X
Z=X.det() #defines polynomial in u aka inverse of the Ihara zeta function
Z #computes determinant of X
Z.coefficients(u) #extracts coefficients
considering my graph is a complete graph on 4 vertices - the coefficients should be as such:
[coeff,degree of u]
[1,0], [0,1], [0,2],[-8,3],[-2,4]
**NOTE:**
im only interested in coefficients up to the order of n=#of nodes in the graph, so here for K_4 obviously n=4.
where the coefficient of u^3 corresponds to the negative of twice the number of triangles in K_4
where the coefficient u^4 corresponds to the negative of twice the number of squares in K_4
**Here is an image of a K_4 graph minus an edge and the line graph construction of K_4 that i want**
![Here is an image of a K_4 graph minus an edge and the line graph construction of K_4 that i am after](http://dl.dropbox.com/u/2399196/graph.png)jtaaFri, 22 Feb 2013 13:59:05 -0600http://ask.sagemath.org/question/9835/