ASKSAGE: Sage Q&A Forum - Latest question feedhttp://ask.sagemath.org/questions/Q&A Forum for SageenCopyright Sage, 2010. Some rights reserved under creative commons license.Sat, 10 Jun 2017 14:16:34 -0500Help with unstable codehttp://ask.sagemath.org/question/37907/help-with-unstable-code/ This basically continues from a previous post: [generation of certain matrices](https://ask.sagemath.org/question/37860/generation-of-certain-matrices/)
I'm trying to draw circles in the plane by using fractional linear transformations.
Here is my code:
K = NumberField(x^2 + 2, 's')
OK = K.ring_of_integers()
def FLT(M,z):
"""takes the fractional linear transformation/Mobius transformation of a z in CC"""
if z == 'infinity' and M[1,0] != 0:
return M[0,0]/M[1,0]
elif z == 'infinity' and M[1,0] == 0:
return 'infinity'
elif M[1,0] != 0 and z == -M[1,1]/M[1,0]:
return 'infinity'
else:
return (M[0,0]*z+M[0,1])/(M[1,0]*z + M[1,1])
Now generate circles based on 3 image points of a matrix M with entries in the ring OK via FLT:
var('a','b','r','x','y')
func_cir=(x-a)**2+(y-b)**2==r**2
circles = set()
j = 0
while j < 10:
M = random_matrix(OK,2,algorithm = 'unimodular')
if FLT(M,-1) != 'infinity' and FLT(M,0) != 'infinity' and FLT(M,1) != 'infinity':
pta=[FLT(M,-1)[0],FLT(M,-1)[1]]
ptb=[FLT(M,0)[0],FLT(M,0)[1]]
ptc=[FLT(M,1)[0],FLT(M,1)[1]]
eq1 = func_cir.subs(x==pta[0]).subs(y==pta[1])
eq2 = func_cir.subs(x==ptb[0]).subs(y==ptb[1])
eq3 = func_cir.subs(x==ptc[0]).subs(y==ptc[1])
sol = solve([eq1,eq2,eq3],a,b,r)
C = circle((sol[1][0].rhs(),sol[1][1].rhs()),sol[1][2].rhs())
circles.add(C)
j += 1
This second chunk of code throws the error "list index out of range" about 50% of the time. I thought that it may have been due to division by zero, but now I'm not so sure. I've also tried using a for loop with the exact same result.
Thank you very much for the help!
Daniel LSat, 10 Jun 2017 14:16:34 -0500http://ask.sagemath.org/question/37907/