ASKSAGE: Sage Q&A Forum - RSS feedhttps://ask.sagemath.org/questions/Q&A Forum for SageenCopyright Sage, 2010. Some rights reserved under creative commons license.Sat, 29 Jun 2019 19:01:11 +0200Calculating Cauchy Integrals in Sagehttps://ask.sagemath.org/question/47017/calculating-cauchy-integrals-in-sage/Hi!
I am relatively new to complex analysis and I am trying to write down the following integral in Sage Math:
$$
I(k) = \frac{1}{2i\pi}\oint\frac{(1-t^2)}{(1-t)^n}\frac{dt}{t^{k+1}}
$$
from a paper that can be found at:
http://magali.bardet.free.fr/Publis/ltx43BF.pdf
The contour is a unit circle around the origin with a radius less than 1.
whereby $$S(n) = \frac{(1-t^2)}{(1-t)^n} $$ is a formal power series. The Cauchy Integral will produce the k-th coefficient of $S(n)$. I tried doing the following:
<!-- language: python -->
def deg_reg_Cauchy(k, n, m):
R.<t> = PowerSeriesRing(CC, 't')
constant_term = 1/(2*I*pi)
s = (1-t**2)**m / (t**(k+1)*(1-t)**n)
s1 = constant_term * s.integral()
return s1
I realize this is probably ***very*** wrong and I used $0$ till $2\pi$ as simple placeholders until I find appropriate values. Does anyone have any tips on how to go about this, please? Below is the error message that is being outputted by Sage.
<!-- language: python -->
ArithmeticError: The integral of is not a Laurent series, since t^-1 has nonzero coefficient.
Thank you!JoaoDDuarteSat, 29 Jun 2019 19:01:11 +0200https://ask.sagemath.org/question/47017/