ASKSAGE: Sage Q&A Forum - RSS feedhttps://ask.sagemath.org/questions/Q&A Forum for SageenCopyright Sage, 2010. Some rights reserved under creative commons license.Tue, 17 Mar 2015 19:38:39 +0100implementing Lie-admissible algebrashttps://ask.sagemath.org/question/26229/implementing-lie-admissible-algebras/How would I implement [Lie-admissible algebras](http://www.encyclopediaofmath.org/index.php/Lie-admissible_algebra) in Sage?
A Lie-admissible algebra is "A (non-associative) algebra (cf. [Non-associative rings and algebras](http://www.encyclopediaofmath.org/index.php/Non-associative_rings_and_algebras)) whose commutator algebra becomes a Lie algebra." [Read more.](http://www.encyclopediaofmath.org/index.php/Lie-admissible_algebra)
Lie-admissible algebras are classified as [17D25](https://zbmath.org/classification/?q=cc:17D25) on MSC2010.GeremiaTue, 17 Mar 2015 19:38:39 +0100https://ask.sagemath.org/question/26229/Quotienting a ring of integershttps://ask.sagemath.org/question/9556/quotienting-a-ring-of-integers/I was trying to play within the ring of integers of a number field, when I decided to quotient by an ideal. It raised an "IndexError: the number of names must equal the number of generators" exception, which was quite unexpected ; here is an example:
K=NumberField(x**2+1,x)
O=K.ring_of_integers()
O.quo(O.ideal(3))
as you see, I'm using the same ring to define the ideal I want to quotient with, so there is mathematically no problem... so I think either I found a bug or something needs to be documented better. How does one work in a quotient of a ring of integers?SnarkThu, 22 Nov 2012 01:52:30 +0100https://ask.sagemath.org/question/9556/Polynomial.https://ask.sagemath.org/question/8743/polynomial/I've a question. Is in Sage a function, method, whatever, what can show me step by step, how solve, for example: polynomial "n" grade?
Thanks for answers, Ani.AniMon, 27 Feb 2012 11:44:43 +0100https://ask.sagemath.org/question/8743/