ASKSAGE: Sage Q&A Forum - RSS feedhttps://ask.sagemath.org/questions/Q&A Forum for SageenCopyright Sage, 2010. Some rights reserved under creative commons license.Thu, 28 Mar 2019 06:29:57 +0100ideal membership and solutionhttps://ask.sagemath.org/question/45932/ideal-membership-and-solution/I gave sage the following ring and the ideal
R.<x,y,z>=GF(2)[];
f=1 + z + y*z + y^2*z + z^2 + y*z^2;
g=1 + x + y^2 + z^2;
I = R.ideal(f, g)
I found that the function h below lies in the Ideal I using
h=1 + y + z + x*z + y*z + x*y*z + y^2*z + y*z^2;
h in I
I know that in general, finding polynomials $a(x)$ and $b(x)$ such that $h = a f+ b g$ might be hard, but can I find the solutions for $a$ and $b$ to a certain degree of these polynomials, if they exist? I was wondering if sage can check this more efficiently
arpitThu, 28 Mar 2019 06:29:57 +0100https://ask.sagemath.org/question/45932/