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 | 1 | initial version |
I asked this very same question on Math Stack Exchange and someone else pointed out my very silly mistake: When constructing the matrix P_B I omitted a minus sign for the last entry of the second row. The correct matrix is P_B = Matrix([[5/9,
-4/9*I, -2/9*I],[4/9*I, 5/9, -2/9],[2/9*I, -2/9, 8/9]]), which is both idempotent and self-adjoint, i.e. represents and orthogonal projection with respect to the standard basis of $\mathbb{C}^3$.
| | 2 | No.2 Revision |
I asked this very same question on Math Stack Exchange and someone else pointed out my very silly mistake: When constructing the matrix P_B I omitted a minus sign for the last entry of the second row. The correct matrix is P_B = Matrix([[5/9,
-4/9*I, -2/9*I],[4/9*I, 5/9, -2/9],[2/9*I, -2/9, 8/9]]), which is both idempotent and self-adjoint, i.e. represents and an orthogonal projection with respect to the standard basis of $\mathbb{C}^3$.
